5 years ago in Quantitative Aptitude

Provided Sin(A-B) = SinACosB - CosASinB, then Sin15will be?

[A] \[\frac{\sqrt{3}}{2\sqrt{2}}\]
[B] \[\frac{\sqrt{3}-1}{2\sqrt{2}}\]
[C] \[\frac{\sqrt{3}+1}{2\sqrt{2}}\]
[D] \[\frac{\sqrt{3}-1}{\sqrt{2}}\]
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Answers

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ram manohar
ram manohar - 2 years ago

ram manohar from Hyderabad, India is saying \[\frac{\sqrt{3}-1}{\sqrt{2}}\] is correct answer

Nazia Sayed
Nazia Sayed - 2 years ago

Nazia Sayed from Mumbai, India is saying \[\frac{\sqrt{3}-1}{2\sqrt{2}}\] is correct answer

Sayed badruzama
Sayed badruzama - 3 years ago

Sayed badruzama from Mumbai, India is saying \[\frac{\sqrt{3}-1}{2\sqrt{2}}\] is correct answer

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