5 years ago in Quantitative Aptitude

# Provided Sin(A-B) = SinACosB - CosASinB, then Sin15o will be?

[A] $\frac{\sqrt{3}}{2\sqrt{2}}$
[B] $\frac{\sqrt{3}-1}{2\sqrt{2}}$
[C] $\frac{\sqrt{3}+1}{2\sqrt{2}}$
[D] $\frac{\sqrt{3}-1}{\sqrt{2}}$

## Overall Stats

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Incorrect 1
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ram manohar - 2 years ago

ram manohar from Hyderabad, India is saying $\frac{\sqrt{3}-1}{\sqrt{2}}$ is correct answer

Nazia Sayed - 2 years ago

Nazia Sayed from Mumbai, India is saying $\frac{\sqrt{3}-1}{2\sqrt{2}}$ is correct answer

Sayed badruzama - 3 years ago

Sayed badruzama from Mumbai, India is saying $\frac{\sqrt{3}-1}{2\sqrt{2}}$ is correct answer

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