2 years ago in Problems on Ages

# The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:

[A] 5 : 2
[B] 7 : 3
[C] 9 : 2
[D] 13 : 4

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## Related Questions

### The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).

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• [D] None of these

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