2 years ago in Problems on Ages

# The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).

[A] 8, 20, 28
[B] 16, 28, 36
[C] 20, 35, 45
[D] None of these

## Overall Stats

Attempted 4
Correct 0
Incorrect 1
Viewed 3

Aiman Faisal - 9 months ago

Aiman Faisal from Noida, India is saying 20, 35, 45 is correct answer

## Related Questions

• [A] 14 years
• [B] 19 years
• [C] 33 years
• [D] 38 years

• [A] 5 : 2
• [B] 7 : 3
• [C] 9 : 2
• [D] 13 : 4

### Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?

• [A] 24
• [B] 27
• [C] 40
• [D] Cannot be determined
• [E] None of these

### A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:

• [A] 14 years
• [B] 18 years
• [C] 20 years
• [D] 22 years
• [E] None of these

### Sachin is younger than Rahul by 7 years. If their ages are in the respective ratio of 7 : 9, how old is Sachin?

• [A] 16 years
• [B] 18 years
• [C] 28 years
• [D] 24.5 years
• [E] None of these