A fuel dealer mixes two brands of fuel which cost in the ratio 2:3. A solution containing 30% Brand A and remaining Brand B yields profit of 10% when sold at RS 297. What is cost of brand B?
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Answers
Let quantity of solution sold be 1 litre
When the solution is sold for 297, the profit percent = 10%
Hence CP of of solution = SP × 100/(100+P%)
⇒CP = 297 × 100/(100+10)
⇒CP = 270
Ratio of quantities of brand A and brand B is 3:7
Let their costs be 2c and 3c.
⇒ 0.3×2c + 0.7×3c = 270
⇒ 2.7c = 270
⇒ c = 100
Hence cost of Brand B = 3c = 300

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