# IB ACIO Grade - II Solved Question Paper - 15th September 2013

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## Police and Security : IB ACIO Grade - II 2013

Solved Paper of Assistant Central Intelligence Officer (ACIO) Grade - II Examination 2013 held on 15th September 2013. Multiple choice Questions with Answers of Intelligence Bureau India Examination of year 2013. The paper-1 consist of 100 objective**1.**If increasing 20 by P percent gives the same result as decreasing 60 by P percent, what is P percentage of 70?

**Answer: ** D. 35

**Explanation: **

\[Decrease\ 60\ by\ P\ percentage:\ 60 - P\% of\ 60\ = 60 - \frac{60P}{100}=60 - \frac{3P}{5}\]

\[According\ to\ Question:\ 20 +\frac{P}{5} = 60 - \frac{3P}{5}\]

\[By\ solving\ we\ get\ P\ =\ 50\]

\[Now\ P\ percentage\ of\ 70\ means\ 50\%\ OF\ 70\ = \frac{50}{100}70\ =\ 35\]

**2.**If republic day of India in 1980 falls on Saturday, X was born on March 3 1980 and Y is older to X by four days, then Y's birthday fell on?

**Answer: ** B. Friday

**Explanation: **

**3.**Find the missing number in the following series:

4,8,....,100,180,294

**Answer: ** C. 48

**Explanation: **

**4.**There are six tasks and six persons. Task 1 can not be assigned to either person 1 or 2; task 2 must be assigned to either person 3 or 4. Every person has to be assigned a task. In how many ways can this assignment be done?

**Answer: ** A. 144

**Explanation: **

Task 2 can be assigned to either person 3 or 4, hence total number of ways in which task 2 can be assigned = 2 ways

Task 3 can be assigned in = 4 ways i.e 6 -4 as two tasks are already assigned.

Similarly Task 4, 5 and 6 can be assigned in 3,2,1 ways respectively.

Hence total number of ways in which this assignment can be done = 4 x 2 x 4 x 3 x 2 x 1 = 192 ways.

**5.**A number when divided by a divisor leaves a remainder of 24.When twice the original number is divided by the same divisor, the remainder is 11. What is the value of divisor?

**Answer: ** D. 37

**Explanation: **

Hence X = DQ+R

According to question:

X = DQ + 24 ...... (i)

Now twice the original number

2X = 2(DQ+24) [From eqn (i)]

It is divided by the same divisor D

[2(DQ+24)]/D = 2DQ/D+48/D

2DQ/D leaves 0 as remainder as D cancles Hence 48/D = 11 (According to question) So if we subtract 11 from 48 it becomes 37 (i.e 48-11=37)

**Hence the correct Answer is 37**

**6.**In how many ways can 15 people be seated around two round tables with seating capacities of 7 and 8 people?

**Answer: ** C. (15C8) * 6! * 7!

**Explanation: **

Pick 8 people out of 15 in 15

_{C8}ways

Now 8 people can be seated in (8-1)! and remaining 7 people can be seated in (7-1)! ways.

**Hence required number of ways = 15**

_{C8}* 7! * 6!**7.**What is the sum of all positive integers lying between 200 and 400 that are multiple of 7?

**Answer: ** A. 8729

**Explanation: **

**8.**The difference between the ages of two brothers is a prime number. Sum of their ages is also a prime number. If the elder brother is 28 years old, how many different values can the age of the younger brother take?

**Answer: ** B. 3

**9.**Find the least five digit number which on divided by 12,18,21,28 leaves the same remainder.

**Answer: ** B. 10081

**10.**In what ratio should a 20% methyl alcohol solution be mixed with a 50% methyl alcohol solution so that the resultant solution has 40% methyl alcohol in it ?

**Answer: ** A. 1:2

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