Mathematics

Write the complement of ${ 51 }^{ \circ } ,28^{ \circ },13^{ \circ }\$?

SOLUTION
The complement of ${ 51 }^{ o }$ is ${ 90 }^{ o }-{ 51 }^{ o }={ 39 }^{ o }.$

The complement of ${ 28 }^{ o }$ is ${ 90 }^{ o }-{ 28 }^{ o }={ 62 }^{ o }.$

The complement of ${ 13 }^{ o }$ is ${ 90 }^{ o }-{ 13 }^{ o }={ 77 }^{ o }.$

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Subjective Medium Published on 09th 09, 2020
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