Mathematics

Write the complement of $${ 51 }^{ \circ  } ,28^{ \circ  },13^{ \circ  }\ $$?


SOLUTION
The complement of $${ 51 }^{ o  }$$ is $${ 90 }^{ o  }-{ 51 }^{ o  }={ 39 }^{ o  }.$$

The complement of $${ 28 }^{ o  }$$ is $${ 90 }^{ o  }-{ 28 }^{ o  }={ 62 }^{ o  }.$$

The complement of $${ 13 }^{ o  }$$ is $${ 90 }^{ o  }-{ 13 }^{ o  }={ 77 }^{ o  }.$$
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Subjective Medium Published on 09th 09, 2020
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