Mathematics

# Write the complement angle of:$(x-10)^{o}$

##### SOLUTION
The complement angle of $(x-10)^{o}$ is,
$=90^{o}-(x-10)^{o}$
$=90^{o}-x^{o}+10^{o}$
$=100^{o}-x^{o}$
$=(100-x)^{o}$
Therefore, the complement of $(x-10)^{o}$ is $(100-x)^{o}$

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Subjective Medium Published on 09th 09, 2020
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