Mathematics

Write the complement angle of:
$$(x-10)^{o}$$


SOLUTION
The complement angle of $$(x-10)^{o}$$ is,
$$=90^{o}-(x-10)^{o}$$
$$=90^{o}-x^{o}+10^{o}$$
$$=100^{o}-x^{o}$$
$$=(100-x)^{o}$$
Therefore, the complement of $$(x-10)^{o}$$ is $$(100-x)^{o}$$
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