Mathematics

Two supplementary angles differ by $48^o$. Find the angles.

$66^o, 114^o$

SOLUTION
Supplementary angles add up to form $180$
Let one angle be $x$ and other be $180 - x$
Hence, $x - (180- x) =48$    ....(Given)
$\Rightarrow x- 180+ x= 48$
$\Rightarrow 2x= 48+ 180= 228$
$\Rightarrow x= \dfrac { 228 }{ 2 } = 114$
Hence, other angle $= 180- x= 180- 114= 66$
Two angles are $114$ and 66$. You're just one step away Create your Digital Resume For FREE on your name's sub domain "yourname.wcard.io". Register Here! Single Correct Medium Published on 09th 09, 2020 Questions 120418 Subjects 10 Chapters 88 Enrolled Students 86 Realted Questions Q1 Single Correct Medium The straight lines$AB$and$CD$intersect at$E$. If$EF$and$EG$are bisectors of$\angle DEA$and$\angle AEC$respectively and if$\angle AEF=x$and$\angle AEG=y$, then • A.$x+y>{90}^{o}$• B.$x+y< {90}^{o}$• C.$x+y={180}^{o}$• D.$x+y={90}^{o}

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