Mathematics

Two supplementary angles differ by $$48^o$$. Find the angles.


ANSWER

$$66^o, 114^o$$


SOLUTION
Supplementary angles add up to form $$ 180$$
Let one angle be $$x$$ and other be $$ 180 - x$$
Hence, $$x - (180- x) =48$$    ....(Given)
$$ \Rightarrow x- 180+ x= 48$$
$$ \Rightarrow 2x= 48+ 180= 228$$
$$\Rightarrow x= \dfrac { 228 }{ 2 } = 114$$ 
Hence, other angle $$= 180- x= 180- 114= 66$$
Two angles are $$ 114$$ and 66$$.
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