Mathematics

# Two supplementary angles differ by $34^o$. Then the angles are __________.

$107^o, 73^o$

##### SOLUTION
Let two supplementary angles are $x$ and $y$
We know, $x+y=180^o$    ....(1)
As given in the question $x-y=34^o$
$\Rightarrow x=34+y$     .....(2)
Putting the value of $x$ in terms of $y$ in the eqn (1) we get
$34+y+y=180\\ \Rightarrow 2y=146\\ \Rightarrow y=73^o$
And $x=34+y$
$=34+73$
$=107^o$
Therefore, the angles are $107^0$ and $73^0$.

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Single Correct Medium Published on 09th 09, 2020
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