Mathematics

The value of $$\displaystyle \underset{0}{\overset{x}{\int}} \dfrac{(t - |t|)^2}{(1 + t^2)} dt$$ is equal to 


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$$4(x - \tan^{-1} x), \, \ \text{if} \, x < 0$$


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Single Correct Medium Published on 17th 09, 2020
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