Mathematics

The value of $$\displaystyle \int \dfrac {dx}{(1+\sqrt {x})\sqrt {x-x^{2}}}$$ is equal to


ANSWER

$$\dfrac {2(\sqrt {x}+1)}{\sqrt {1-x}}+c$$


View Full Answer

Its FREE, you're just one step away


Single Correct Medium Published on 17th 09, 2020
Next Question
Questions 203525
Subjects 9
Chapters 126
Enrolled Students 86
Enroll Now For FREE

Realted Questions

Q1 Single Correct Medium
$$\int _ { 0 } ^ { \pi } \dfrac { \sin \theta + \cos \theta } { \sqrt { 1 + \sin 2 \theta } } d \theta =$$
  • A. $$\pi + \lambda$$ and $$\lambda > 0$$
  • B. $$\pi / 2$$
  • C. $$\pi / 3$$
  • D. $$\pi$$

Asked in: Mathematics - Integrals


1 Verified Answer | Published on 17th 09, 2020

View Answer
Q2 Single Correct Medium

$$\displaystyle \int_{0}^{\infty}\frac{x^{2}dx}{(1+x^{2})^{7/2}}=$$
  • A. 1/15
  • B. -1/15
  • C. $$\displaystyle \frac{4}{15}$$
  • D. 2/15

Asked in: Mathematics - Integrals


1 Verified Answer | Published on 17th 09, 2020

View Answer
Q3 Single Correct Hard
If $$I_{1} = \int_{0}^{1} 2^{x^{3}} dx, I_{2} = \int_{0}^{1}2^{x^{2}}dx, I_{3} = \int_{1}^{2}2^{x^{2}}dx$$ and $$I_{4} = \int_{1}^{2}2^{x^{3}}dx$$, then
  • A. $$I_{2} > I_{1}$$
  • B. $$I_{3} > I_{4}$$
  • C. $$I_{1} > I_{3}$$
  • D. $$I_{1} > I_{2}$$

Asked in: Mathematics - Integrals


1 Verified Answer | Published on 17th 09, 2020

View Answer
Q4 Subjective Medium
Evaluate the following integral: $$\displaystyle\int_{-1}^{1}|2x+1|\ dx$$

Asked in: Mathematics - Integrals


1 Verified Answer | Published on 17th 09, 2020

View Answer
Q5 Subjective Medium
The value of $$\displaystyle\int\limits_{-1}^{1}\sin ^{11}x.\cos^{12}x\ dx$$.

Asked in: Mathematics - Integrals


1 Verified Answer | Published on 17th 09, 2020

View Answer