Mathematics

The numbers of points of intersection of $2y=1$ and $y=\sin\,x$, in $-2\pi\le x\le 2\pi$ is

$4$

SOLUTION
Given $y=\dfrac{1}{2},\,y=sin\,x$

$\Rightarrow\,sin\,x=\dfrac{1}{2}$

But $-2\pi\le\,x\,\le\,2\pi$ (Given)

Hence, $x=\dfrac{\pi}{6},\,\dfrac{5\pi}{6},\,\dfrac{-7\pi}{6},\,\dfrac{-11\pi}{6}$

Therefore, number of solutions $=4$

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Single Correct Medium Published on 09th 09, 2020
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