Mathematics

The difference of two complementary angles is $$30^o$$. Then, the angles are 


ANSWER

$$60^o, 30^o$$


SOLUTION
Option (a) is correct.
Let the $$x$$ and $$y$$ are the angles
$$x+y=90^o$$ ....(1) [ Complementary angle]
$$x-y=30^o$$    ....(2) [ given ]
By addition of both equations, we get 
$$\Rightarrow 2x=120^o$$
$$\Rightarrow x=\dfrac{120^o}{2}$$
$$\Rightarrow x=60^o$$
Putting the value of $$x$$ in equation $$1$$, we get 
$$\Rightarrow 60+y=90^o$$
$$\Rightarrow y=90^o -60^o$$
$$\Rightarrow y=30^o$$
Therefore, the required angles are $$30$$ and $$60$$ degrees.
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