Mathematics

The complement of $$(90^\circ-a)$$ is :


ANSWER

a


SOLUTION
Let the complement be $$x$$
Sum of complementary angles is $$90^{\circ}$$
$$\Rightarrow x+{ (90-a) }^{ \circ  }={ 90 }^{ \circ  }\\ \Rightarrow x-a={ 90 }^{ \circ  }-{ 90 }^{ \circ  }\\ \Rightarrow x=a$$
So the complement is $$a$$
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