Mathematics

# The complement of $(90^\circ-a)$ is :

a

##### SOLUTION
Let the complement be $x$
Sum of complementary angles is $90^{\circ}$
$\Rightarrow x+{ (90-a) }^{ \circ }={ 90 }^{ \circ }\\ \Rightarrow x-a={ 90 }^{ \circ }-{ 90 }^{ \circ }\\ \Rightarrow x=a$
So the complement is $a$

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Single Correct Medium Published on 09th 09, 2020
Questions 120418
Subjects 10
Chapters 88
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