Physics

# The % by volume of ${ C }_{ 4 }{ H }_{ 10 }$ in a gaseous mixture of ${ C }_{ 4 }{ H }_{ 10 }, { C }H_{ 4 }\ and\ CO$ is 40. When 200 ml of the mixture is burnt in excess of $O_{ 4 }$ produced.

440

##### SOLUTION
$C_4H_{10}+\dfrac{13}{2}O_2\rightarrow KO_2+5H_2O$
$CO+\dfrac{1}{2}O_2\rightarrow CO_2\uparrow H_2O$
$\therefore$ total volume of $CO_2$ produced
$=4\times volume \,of\, C_4H_{10}$
$=1\times (volume \,of \,CO)$
$=4\times 80\times 120$
$=440ml$

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