Mathematics

# The angle which exceeds its complement by $20^o$ is:

$55^o$

##### SOLUTION
Let the angle be $x$
$\therefore complement = (90-x)$
$x + (x+20 ) = 90$
$2x = 90-20$
$x = \dfrac{70}{2}$
$x = 35^o$
$\therefore$  other angle = $90 - 35 = 55^o$

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Single Correct Medium Published on 09th 09, 2020
Questions 120431
Subjects 10
Chapters 88
Enrolled Students 151

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