Mathematics

# Solve:$\displaystyle \int_{0}^{4} {4x-x^2}dx$

##### SOLUTION
Given $\displaystyle \int_{0}^{4} {4x-x^2}dx$

$=\left. 2x^2-\dfrac{x^3}3 \right]_0^4$        [$\because \displaystyle\int x^n=\dfrac{x^{n+1}}{n+1}$]

$=32-\dfrac{64}3$

$=\dfrac {32}3$

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Subjective Medium Published on 17th 09, 2020
Questions 203525
Subjects 9
Chapters 126
Enrolled Students 86

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