Mathematics

Solve:

$$\displaystyle \int_{0}^{4} {4x-x^2}dx$$


SOLUTION
Given $$\displaystyle \int_{0}^{4} {4x-x^2}dx$$

$$=\left. 2x^2-\dfrac{x^3}3 \right]_0^4$$        [$$\because \displaystyle\int x^n=\dfrac{x^{n+1}}{n+1}$$]

$$=32-\dfrac{64}3 $$ 

$$=\dfrac {32}3$$
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Subjective Medium Published on 17th 09, 2020
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