Mathematics

# Solve $I=\int \frac{4x+1}{\sqrt{2x^{2}+x-3}}$

##### SOLUTION
$I=\int{\dfrac{4x+1}{\sqrt{2{x}^{2}+x-3}}}dx$
Let $2x^{2}+x-3=t$
Differentiating, $\left(4x+1\right)dx=dt$
$\therefore I=\int{\dfrac{dt}{\sqrt{t}}}$
$=2t^{1/2}$
$=2 (2{x^{2}+x-3})^{1/2}$

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Subjective Medium Published on 17th 09, 2020
Questions 203525
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