Mathematics

# Solve $\displaystyle\int {\dfrac{{{x^5}}}{{{x^2} + 1}}} dx$

$\dfrac{{{x^4}}}{4} - \dfrac{{{x^2}}}{2} + \dfrac{1}{2}\log \left( {{x^2} + 1} \right) + c$

##### SOLUTION

Consider the given integral.

$I=\int{\dfrac{{{x}^{5}}}{{{x}^{2}}+1}}dx$

$I=\int{\left( {{x}^{3}}-x+\dfrac{x}{{{x}^{2}}+1} \right)}dx$

$I=\int{\left( {{x}^{3}}-x+\dfrac{1}{2}\left( \dfrac{2x}{{{x}^{2}}+1} \right) \right)}dx$

$I=\dfrac{{{x}^{4}}}{4}-\dfrac{{{x}^{2}}}{2}+\dfrac{1}{2}{{\log }_{e}}\left( {{x}^{2}}+1 \right)+C$

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Single Correct Medium Published on 17th 09, 2020
Questions 203525
Subjects 9
Chapters 126
Enrolled Students 84

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