Mathematics

Solve: $$\displaystyle \overset{2}{\underset{0}{\int}} (3x^2 - 1)dx$$.


SOLUTION
$$\displaystyle\int^2_0(3x^2-1)dx$$
$$=\displaystyle\int^2_03x^2dx-\displaystyle\int^2_0dx$$
$$=\dfrac{3x^3}{3}\displaystyle\int^2_0-x\displaystyle\int^2_0$$
$$=(8-0)-(2-0)$$
$$=8-2$$
$$=6$$
$$\therefore \displaystyle\int^2_0(3x^2-1)dx=6$$.
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Subjective Medium Published on 17th 09, 2020
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