Mathematics

Solve $$\displaystyle \int \sec^{2}(7-4x) dx$$


SOLUTION
$$\int \sec^{2} (7 - 4x)dx $$

$$= \tan (7 - 4x) \dfrac{d}{dx} (7 - 4x) + c$$

$$= \tan (7 - 4x) (- 4) + c$$

$$ = -4 \tan (7 - 4x) + c$$  (Ans)
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Subjective Medium Published on 17th 09, 2020
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