Mathematics

Solve $$\displaystyle \int {\frac{x}{{1 - {x^3}}}dx} $$


SOLUTION
View Full Answer

Its FREE, you're just one step away


Subjective Medium Published on 17th 09, 2020
Next Question
Questions 203525
Subjects 9
Chapters 126
Enrolled Students 84
Enroll Now For FREE

Realted Questions

Q1 Single Correct Medium
$$\int_{0}^{1}\dfrac{\sin t}{1+t}dt=\alpha$$, then the value of $$\int_{4\pi-2}^{4\pi}\dfrac{\sin (t/2)}{4\pi+2-t}dt=$$
  • A. $$-\alpha$$
  • B. $$2\alpha$$
  • C. $$4\pi-2\alpha$$
  • D. $$\alpha$$

Asked in: Mathematics - Integrals


1 Verified Answer | Published on 17th 09, 2020

View Answer
Q2 Subjective Hard
$$\displaystyle\int \dfrac{x^2}{\sqrt{1-x}}dx$$ is equal to?

Asked in: Mathematics - Integrals


1 Verified Answer | Published on 17th 09, 2020

View Answer
Q3 Single Correct Hard
The value of $$\displaystyle \int { { e }^{ 2x } } \left( \frac { 1 }{ x } -\frac { 1 }{ 2{ x }^{ 2 } }  \right) dx$$ is
  • A. $$\displaystyle \frac { { e }^{ 2x } }{ 2 } +c$$
  • B. $$\displaystyle \frac { { e }^{ 2x } }{ 3x } +c$$
  • C. $$\displaystyle \frac { { e }^{ 2x } }{ x } +c$$
  • D. $$\displaystyle \frac { { e }^{ 2x } }{ 2x } +c$$

Asked in: Mathematics - Integrals


1 Verified Answer | Published on 17th 09, 2020

View Answer
Q4 Subjective Medium
The value of $$\int {\dfrac{{dx}}{{\sin x.\sin \left( {x + \alpha } \right)}}} $$ is equal to

Asked in: Mathematics - Integrals


1 Verified Answer | Published on 17th 09, 2020

View Answer
Q5 Passage Medium
Consider two differentiable functions $$f(x), g(x)$$ satisfying $$\displaystyle 6\int f(x)g(x)dx=x^{6}+3x^{4}+3x^{2}+c$$ & $$\displaystyle 2 \int \frac {g(x)dx}{f(x)}=x^{2}+c$$. where $$\displaystyle f(x)>0    \forall  x \in  R$$

On the basis of above information, answer the following questions :

Asked in: Mathematics - Limits and Derivatives


1 Verified Answer | Published on 17th 08, 2020

View Answer