Mathematics

Solve : $$\displaystyle \int _0^3 x^3+2x+8 dx $$


ANSWER

$$\dfrac {213}4$$


SOLUTION
consider, $$I=\displaystyle \int_0^3 (x^3 + 2x + 3)dx$$

$$=\displaystyle \int_0^3 x^3dx + \int_0^3 2xdx + \int_0^38dx$$

$$=\left[\dfrac{x^4}{4}\right]^3_0 + [x^2]^3_0 + [8x]^3_0$$

$$=\dfrac{81}{4} + 9 + 24 = \dfrac{213}{4}$$
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Single Correct Medium Published on 17th 09, 2020
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