Mathematics
##### ASSERTION

$\int_{0}^{\pi }\sqrt{1-\sin ^{2}x}dx=0$.

##### REASON

$\int_{0}^{\pi }\cos xdx=0.$

##### ANSWER

Assertion is incorrect but Reason is correct

##### SOLUTION
$\int_{0}^{\pi }\sqrt{1-\sin ^{2}x}dx$
$=\int_{0}^{\pi }\left | \cos x \right |dx$
$=\int_{0}^{\frac{\pi}{2} }\cos xdx+\int_{\frac{\pi}{2}}^{\pi }-\cos xdx$
$=1+1=2$
Hence, statement $1$ is false.
However, statement $2$ is true.

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Assertion & Reason Medium Published on 17th 09, 2020
Questions 203525
Subjects 9
Chapters 126
Enrolled Students 86

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