Mathematics

# $PQ=1.28cm, PR=2.56cm, PE=0.18cm$ and $PF=0.36cm$

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##### SOLUTION
Given PQ=1.28 cm,PR=2.56 cm,PE=0.18 cm and PF=0.36 cm where E and F are points on PQ and PR respectively.
Now, $\dfrac{PE}{PQ} = \dfrac{0.18}{1.28} = \dfrac{9}{64}$
$\dfrac{PF}{PR} = \dfrac{0.36}{2.56} = \dfrac{9}{64}$
thus, $\dfrac{PE}{PQ} = \dfrac{PF}{PR}$
By converse of equal Intercept theorem, $EF \parallel QR$

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Single Correct Medium Published on 09th 09, 2020
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