Physics

# Multiple Correct Answers TypeWhich of the following pairs have the same dimensions?

$h/e$ and magnetic flux

Electric flux and $a/ \epsilon_0$

##### SOLUTION
$\left[ h \right] =\left[ Joute\times second \right] =\left[ { ML }^{ 2 }{ T }^{ -1 } \right]$
[Magnetic flux] $=$ [Magnetic field $\times$ Area]
$\Rightarrow \quad \left[ \phi \right] =\left[ { MTA }^{ -1 } \right] \left[ { L }^{ 2 } \right]$
$\Rightarrow \quad \left[ \phi \right] =\left[ { ML }^{ 2 }{ TA }^{ -1 } \right]$
And
$\left[ \dfrac { h }{ e } \right] =\left[ \dfrac { { ML }^{ 2 }{ T }^{ -1 } }{ AT } \right] =\left[ { ML }^{ 2 }{ T }^{ -2 }{ A }^{ -1 } \right]$
[Electric flux] $=\left[ E \right] \left[ A \right] =\left[ \dfrac { E }{ q } \right] \left[ A \right]$
$\Rightarrow$  [Electric flux] $=\left[ \dfrac { F }{ IT } \right] \left[ A \right] =\dfrac { \left[ { ML }T^{ -2 } \right] \left[ { L }^{ 2 } \right] }{ AT }$
$=\left[ { ML }^{ 3 }{ T }^{ -3 }{ A }^{ -1 } \right]$

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Multiple Correct Medium Published on 18th 08, 2020
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