Mathematics

Let $$A = \int\limits_0^1 {\cfrac{{{e^t}}}{{1 + t}}dt} $$, then $$\int\limits_{a - 1}^a {\cfrac{{{e^{ - t}}}}{{t - a - 1}}dt} $$ has the value


ANSWER

$$ - A{e^{ - a}}$$


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Single Correct Medium Published on 17th 09, 2020
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