Mathematics

# $\int(tanx -cotx)^{2}dx=$

##### ANSWER

$tanx-cotx-4x+cc$

##### SOLUTION
Now,
$\displaystyle\int (\tan x-\cot x)^2 dx$
$=\displaystyle\int (\tan^2x-2+\cot^2x)dx$
$=\displaystyle\int (\sec^2x-4+\cos ec^2x)dx$
$=\tan x-4x-\cot x+c$. [ Where $c$ is integrating constant]

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Single Correct Medium Published on 17th 09, 2020
Questions 203525
Subjects 9
Chapters 126
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