Mathematics

# $\int sin^{2/3}x cos^{3}x dx$

##### SOLUTION
$\displaystyle\int \sin^{2/3}x\cos^3xdx$
$=\displaystyle\int \sin^{2/3}x\cos^2x\cos xdx$
$=\displaystyle\int \sin^{2/3}x(1-\sin^2x)\cos xdx$
$=\displaystyle\int \sin^{2/3}x\cos xdx-\displaystyle\int \sin^{2/3+2}x\cos xdx$
$=\displaystyle\int \sin^{2/3}x\cos xdx-\displaystyle\int \sin^{5/2}x\cos xdx$
Let $t=\sin x$
$\Rightarrow dt=\cos xdx$
$=\displaystyle\int t^{2/3}dt-\displaystyle\int t^{5/2}dt$
$=\dfrac{t^{2/3+1}}{2/3+1}-\dfrac{t^{5/2+1}}{5/2+1}+c$
$=\dfrac{t^{5/2}}{5/3}-\dfrac{t^{7/2}}{7/2}+c$ where c is the constant of integration
$=\dfrac{3(\sin x)^{5/3}}{5}-\dfrac{2(\sin x)^{7/2}}{7}+c$
$=\dfrac{3\sin^{5/3}x}{5}-\dfrac{2}{7}\sin^{7/2}x+c$ where $t=\sin x$.

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Subjective Medium Published on 17th 09, 2020
Questions 203525
Subjects 9
Chapters 126
Enrolled Students 86

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