Mathematics

# Integrate:$\displaystyle \int \sqrt{2x }$dx

##### SOLUTION
$\displaystyle\int{\sqrt{2x}dx}$

$=\sqrt{2}\displaystyle\int{{x}^{\frac{1}{2}}dx}$

$=\sqrt{2}\dfrac{{x}^{\frac{1}{2}+1}}{\frac{1}{2}+1}$

$=\sqrt{2}\dfrac{{x}^{\frac{3}{2}}}{\dfrac{3}{2}}$

$=\dfrac{2\sqrt{2}x\sqrt{x}}{3}+c$

$=\dfrac{2x\sqrt{2x}}{3}+c$ where $c$ is the constant of integration.

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Subjective Medium Published on 17th 09, 2020
Questions 203525
Subjects 9
Chapters 126
Enrolled Students 84

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