Mathematics

Integrate the following function with respect to $$x$$
$$\dfrac{4x-6}{(x^{2}-3x+5)^{3/2}}$$


SOLUTION
Let,
$$x^2-3x+5=t$$

$$\implies (2x-3)dx=dt$$

Substituting these values, we get

$$\int\dfrac{2dt}{t^{3/2}}$$

$$\implies \dfrac{-2\times2}{t^{1/2}}+C$$

 $$\implies \dfrac{-4}{(x^2-3x+5)^{1/2}}+C$$
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Subjective Medium Published on 17th 09, 2020
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