Mathematics

# $\int {x\sin 3xdx}$

##### SOLUTION
$\int xsin3x dx=x(-cos3x)\frac{1}{3}-\int1\times(-cos3x)\frac{1}{3}dx$

$=\dfrac {-xcos3x}{3}+\dfrac {sin3x}{9} +c$

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Subjective Medium Published on 17th 09, 2020
Questions 203525
Subjects 9
Chapters 126
Enrolled Students 86

#### Realted Questions

Q1 Single Correct Medium
The value of $\displaystyle\int\limits_{-1}^1x|x|\ dx=$
• A. $\dfrac{1}{2}$
• B. $1$
• C. none of these
• D. $0$

1 Verified Answer | Published on 17th 09, 2020

Q2 Single Correct Medium
$\int_{0}^{\pi/4} \sin^{4}x.\cos^{4}xdx=$
• A. $\displaystyle \frac{\pi}{512}$
• B. $\displaystyle \frac{-\pi^{2}}{512}$
• C. $\displaystyle \frac{7\pi}{512}$
• D. $\displaystyle \frac{3\pi}{512}$

1 Verified Answer | Published on 17th 09, 2020

Q3 Subjective Medium
Evaluate:$\displaystyle\int_{0}^{\frac{\pi}{2}}{{\cos}^{2}{x}\,dx}$

1 Verified Answer | Published on 17th 09, 2020

Q4 Subjective Medium
Integrate $\displaystyle\int {\sqrt {\frac{{1 + x}}{{1 - x}}} dx\ , on ( - 1,1)\,.}$

Solve$\int_{}^{} {\left( {2x + 1} \right)\sqrt {x - 4} } dx$