Mathematics

$$\int {\left( {\frac{1}{{\left( {\ell nx} \right)}} - \frac{1}{{{{(\ell nx)}^2}}}} \right)\,dx} $$


SOLUTION

$$\int {\left( {{1 \over {inx}} - {1 \over {inx}}} \right)dn} $$

$$ = \int {1.{1 \over {inx}}dx - \int {{1 \over {{{(inx)}^2}}}dn} } $$

$$ = {x \over {inx}} - \int{ - {1 \over {i{n^2}}}dn - \int {{1 \over {i{n^2}}}dn} } $$

$$ = {x \over {inx}} + c$$

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Subjective Medium Published on 17th 09, 2020
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