Mathematics

$$\int \dfrac { \sin x }{ 1+\cos^2 { x } }dx$$


SOLUTION
$$\displaystyle \int \frac{sin x}{1+ cos^{2}x}dx$$
Put $$cos\, x= 6$$
$$- sinx\, dx = dt$$
$$\displaystyle -\int \frac{1}{1+t^{2}}dt= -Tan^{-1}t\Rightarrow -Tan^{-1}(cos \, x)$$
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Subjective Hard Published on 17th 09, 2020
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