Mathematics

$$\int (ax+b)^{2}$$dx


SOLUTION
We know that $$\dfrac{d}{dx}(ax+b)^{3}=3a(ax+b)^{2}$$

$$\Rightarrow (ax+b)^{2}=\dfrac{1}{3a}\dfrac{d}{dx}(ax+b)^{3}$$

$$\Rightarrow (ax+b)^{2} =\dfrac{d}{dx}[\dfrac{1}{3a}(ax+b)^{3}]$$ 

Thus anti - derivative of $$(ax+b)^{2} is \dfrac{1}{3a}(ax+b)^{3}.$$ 
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Subjective Medium Published on 17th 09, 2020
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