Mathematics

In the figure, AB=CD.Prove that BE=DE and AE=CE where E is the point of intersection of AD and BC.

SOLUTION
In $\triangle{EAB}$ and $\triangle{ECD}$
$AB=CD$   [Given]
$\angle{B}=\angle{D}$   [Angles in the same segment]
$\angle{A}=\angle{C}$   [Angles in the same segment]
$\therefore \triangle{EAB}\cong\triangle{ECD}$    [ASA criteria]
$\therefore BE=DE$       [CPCT]
and $AE=CE$    [CPCT] You're just one step away

Subjective Medium Published on 09th 09, 2020
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Subjects 10
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