Mathematics

# In the adjoining figure,$AOB$ is a straight line. Find the value of $x$, if $\angle AOC =60^0$

##### SOLUTION
Since AOB is a straight line. Therefore,
$\angle AOC +\angle COB=180^{o}$
$60^{o}+x^{o}=180^{o}$
$x^{o}=180^{o} - 60^{\circ}$
$x^{o}=120^{o}$

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Subjective Medium Published on 09th 09, 2020
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