Mathematics

In the adjoining Figure, $\overline{XY}\parallel \overline {BC}$. Find the values of $x, y, z$.

SOLUTION
Given that XY$||$BC
then,
In $\Delta ABC$
$\angle A+\angle B+\angle C=180^o$(property of triangle)
$40^o+30^o+\angle C=180^o$
$70^o+z=180^o$
$z=180^o-70^o$
$z=110^o$
$XY||BC$
then
$\angle x^o=\angle B$
$\angle x^o=30^o$.
Now, In $\Delta AXY$
$\angle x^o+\angle y^o+\angle A=180^o$(property of triangle)
$30^o+\angle y^o=40^o=180^o$
$\angle y^o=180^o-70^o$
$\angle y^o=110^o$ You're just one step away

Subjective Medium Published on 09th 09, 2020
Questions 120418
Subjects 10
Chapters 88
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