Mathematics

# In figure, the value of $a$ is

$10^o$

##### SOLUTION
Option $(D)$ is correct.
$\Rightarrow \angle AOF =COD$ [ vertically opposite angles ]
$\therefore \angle COD =90^o$
Now,
$\angle BOC+\angle COD+\angle EOD=180^{\circ}\cdots\cdots[\because\text{making linear pair}]$
$\Rightarrow 40^o +90^o +5a=180^o$
$\Rightarrow 5a+130^o =180^o$
$\Rightarrow 5a=180^o-130^o$
$\Rightarrow 5a=50^o$
$\Rightarrow a=10^o$

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Single Correct Medium Published on 09th 09, 2020
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