Mathematics

In figure, $$POS$$ is a line, find $$x$$.


SOLUTION
Given,
$$ \angle POQ = 60^o$$
$$\angle QOR= 4x$$
$$\angle ROS = 40^o$$

We know that, the sum of all the angles in a straight line is $$180^o$$

According to the figure,
$$ \angle POQ+\angle QOR+ \angle ROS = 180^o$$
 $$60^o+4x+40^o=180$$
$$100+4x=180^o$$
$$4x=80^o$$
$$x=20^o$$
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Subjective Medium Published on 09th 09, 2020
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