Mathematics

# In figure, $POS$ is a line, find $x$.

##### SOLUTION
Given,
$\angle POQ = 60^o$
$\angle QOR= 4x$
$\angle ROS = 40^o$

We know that, the sum of all the angles in a straight line is $180^o$

According to the figure,
$\angle POQ+\angle QOR+ \angle ROS = 180^o$
$60^o+4x+40^o=180$
$100+4x=180^o$
$4x=80^o$
$x=20^o$

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Subjective Medium Published on 09th 09, 2020
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