Mathematics

In figure, $line\ XY\ ||\ line \ PQ$ and we have $\angle ALY=(2x-15)^o, \angle LMQ=(x+40)^o$, find x.

SOLUTION
We have $\angle ALY=(2x-15)^0$ and $\angle LMQ=(x+40)^0$
Also, $line\ XY\ ||\ line \ PQ$
$\therefore$ $\angle XLM$ and $\angle LMQ$ are corresponding angles.
and corresponding angles on parallel lines are congruent.
$\therefore \angle ALY=\angle LMQ$

$\therefore 2x-15=x+40\\$
$\Rightarrow 2x-x=40+15\\$
$\therefore x=55^0$

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Subjective Medium Published on 09th 09, 2020
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