Mathematics

In Fig.,$$\Delta ODC \sim \Delta OBA,\angle BOC = {125^ \circ }$$ and $$ \angle CDO = {70^ \circ }$$. Find  $$\angle DOC,\angle DCO$$ and $$\angle OAB$$


SOLUTION
By linear angle property,
$$\angle COD+\angle COB=180^o$$
$$\Rightarrow \angle COD=180-125=55^o$$
In $$\Delta COD, 55+70+\angle DCO=180^o$$
$$\Rightarrow \angle DCO=55^o$$
As $$\Delta ODC\sim \Delta OBA$$
$$\Rightarrow \angle OCD=\angle OAB=55^o$$.
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Subjective Medium Published on 09th 09, 2020
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