Mathematics

# In Fig.,$\Delta ODC \sim \Delta OBA,\angle BOC = {125^ \circ }$ and $\angle CDO = {70^ \circ }$. Find  $\angle DOC,\angle DCO$ and $\angle OAB$

##### SOLUTION
By linear angle property,
$\angle COD+\angle COB=180^o$
$\Rightarrow \angle COD=180-125=55^o$
In $\Delta COD, 55+70+\angle DCO=180^o$
$\Rightarrow \angle DCO=55^o$
As $\Delta ODC\sim \Delta OBA$
$\Rightarrow \angle OCD=\angle OAB=55^o$.

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Subjective Medium Published on 09th 09, 2020
Questions 120418
Subjects 10
Chapters 88
Enrolled Students 87

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