Mathematics

In fig, sides  $$QP$$  and  $$RQ$$  of triangle  $$PQR$$  are produced to point  $$S$$  and  $$T$$  respectively. If angle  $$S P R = 135 ^ { \circ }$$  and angle  $$P Q T = 110 ^ { \circ } \text { ,find } \angle P R Q$$.


SOLUTION
REF.Image
So:- $$\angle PQT+\angle PQR= 180$$
$$110+ \angle PQR= 180$$
$$\angle PQR = 70^{\circ}$$
Now, $$\angle SPR+\angle QPR= 180$$
$$135^{\circ}+\angle QPR= 180$$
$$\angle QPR= 45^{\circ}$$
Now,
$$\angle QPR+\angle PQR+\angle QRP= 180$$
$$45+70+\angle QRP = 180$$
$$\angle QRP = 65$$
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Subjective Medium Published on 09th 09, 2020
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