Mathematics

In Fig. if $AB || DE, \angle BAC = 35^o$ and $angle CDE = 53^o$, find $\angle DCE$.

SOLUTION
$\angle BAE=\angle CED$
$\therefore \theta =35^{\circ}$  (Here $AB\parallel DE$, Here AE acts as transverse)

in $\Delta CDE\Rightarrow 53+35+\angle C=180$
$88+\angle C=180^{\circ}$
$\angle C=92^{\circ}$
$\therefore DCE=92^{\circ}$ You're just one step away

Subjective Medium Published on 09th 09, 2020
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