Mathematics

In Fig. if $$AB || DE, \angle BAC = 35^o$$ and $$angle CDE = 53^o$$, find $$\angle DCE$$.


SOLUTION
$$\angle BAE=\angle CED$$ 
$$\therefore \theta =35^{\circ}$$  (Here $$AB\parallel DE$$, Here AE acts as transverse) 

in $$\Delta CDE\Rightarrow 53+35+\angle C=180$$ 
$$88+\angle C=180^{\circ}$$ 
$$\angle C=92^{\circ}$$ 
$$\therefore DCE=92^{\circ}$$
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