Mathematics

If $$y=2^23^{2x}5^{-5}7^{-5}$$ then $$\dfrac{dy}{dx}=$$


SOLUTION
$$y={ 2 }^{ 2 }{ 3 }^{ 2x }{ 5 }^{ -5 }{ 7 }^{ -7 }\\ y={ 2 }^{ 2 }{ 5 }^{ -5 }{ 7 }^{ -7 }{ 3 }^{ 2x }\\ \dfrac { dy }{ dx } ={ 2 }^{ 2 }{ 5 }^{ -5 }{ 7 }^{ -7 }{ 3 }^{ 2x }\log { 2x } \quad (2)\\ \dfrac { dy }{ dx } ={ 2 }^{ 3 }{ 5 }^{ -5 }{ 7 }^{ -7 }{ 3 }^{ 2x }\log { 2x } \quad $$
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Subjective Medium Published on 17th 09, 2020
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