Mathematics

If two supplementary angles differ by $44^o$, then one of the angles is ___________.

$112^o$

SOLUTION
Two supplementary angles differ by $44^o$
$\therefore$ $x+(x+44^o)=180^o$
$2x=136^o$
$x=68^o$
Other angle =$(x+44^o)=(68^o+44^o)=112^o$

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Single Correct Medium Published on 09th 09, 2020
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