Mathematics

If two supplementary angles differ by $$44^o$$, then one of the angles is ___________.


ANSWER

$$112^o$$


SOLUTION
Two supplementary angles differ by $$44^o$$
$$\therefore$$ $$x+(x+44^o)=180^o$$
$$2x=136^o$$
$$x=68^o$$
Other angle =$$(x+44^o)=(68^o+44^o)=112^o$$
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