Mathematics

If the supplement  of an angle is $$130^{\circ}$$, then find its complement.


SOLUTION
Supplement of an angle = $$130^o$$
Let the angle be $$x^o$$
Then, $$x^o + 130^o = 180^o$$
$$\therefore x = 50^o$$
Now, complement of the angle = $$90^o - x = 90^o - 50^o$$
                                                                      $$= 40^o$$
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