Physics

If $L, R, C$ and $V$ respectively represent inductance, resistance, capacitance and potential difference, then the dimensions of $\dfrac { L }{ RCV }$ are the same as those of:

$\dfrac { 1 }{ Current }$

SOLUTION
$L= ML^{2}I^{-2}T^{-2}$
$R= ML^{2}I^{-2}T^{-3}$
$C= M^{-1}L^{-2}I^{2}T^{4}$
$V= ML^{2}I^{-1}T^{-3}$
$\dfrac{L}{RCV}=\dfrac{ML^{2}I^{-2}T^{-2}}{(ML^{2}I^{-2}T^{-3})(M^{-1}L^{-2}I^{2}T^{4})(ML^{2}I^{-1}T^{-3})}$
$\dfrac{L}{RCV}=M^{0}L^{0}T^{0}I^{-1}=\dfrac{1}{current}$
Hence, option D is currect.

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Single Correct Medium Published on 18th 08, 2020
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