Mathematics

If $$ \int _0^1 xdx = \dfrac {\pi}{4} - \dfrac {1}{2} ln 2 $$ then the value of definite integral $$ \int _0^1 \tan^{-1} (1-x+x^2) dx $$ equals :


ANSWER

$$ ln2 $$


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Single Correct Medium Published on 17th 09, 2020
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