Mathematics

If $$f\left (\dfrac {x - 4}{x + 2}\right ) = 2x + 1, (x\epsilon R - \left \{1, -2\right \})$$m then $$\int f(x) dx$$ is equal to
(where $$C$$ is a constant of integration).


ANSWER

$$12\log_{e}|1 - x| - 3x + C$$


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Single Correct Medium Published on 17th 09, 2020
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